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101 lines
3.5 KiB
101 lines
3.5 KiB
13 years ago
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# Thanks to Daenyth for help porting this to Arch Linux.
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import os, platform, re, subprocess
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_distributor_id_cmdline_re = re.compile("(?:Distributor ID:)\s*(.*)", re.I)
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_release_cmdline_re = re.compile("(?:Release:)\s*(.*)", re.I)
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_distributor_id_file_re = re.compile("(?:DISTRIB_ID\s*=)\s*(.*)", re.I)
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_release_file_re = re.compile("(?:DISTRIB_RELEASE\s*=)\s*(.*)", re.I)
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global _distname,_version
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_distname = None
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_version = None
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def get_linux_distro():
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""" Tries to determine the name of the Linux OS distribution name.
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First, try to parse a file named "/etc/lsb-release". If it exists, and
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contains the "DISTRIB_ID=" line and the "DISTRIB_RELEASE=" line, then return
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the strings parsed from that file.
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If that doesn't work, then invoke platform.dist().
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If that doesn't work, then try to execute "lsb_release", as standardized in
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2001:
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http://refspecs.freestandards.org/LSB_1.0.0/gLSB/lsbrelease.html
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The current version of the standard is here:
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http://refspecs.freestandards.org/LSB_3.2.0/LSB-Core-generic/LSB-Core-generic/lsbrelease.html
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that lsb_release emitted, as strings.
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Returns a tuple (distname,version). Distname is what LSB calls a
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"distributor id", e.g. "Ubuntu". Version is what LSB calls a "release",
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e.g. "8.04".
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A version of this has been submitted to python as a patch for the standard
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library module "platform":
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http://bugs.python.org/issue3937
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"""
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global _distname,_version
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if _distname and _version:
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return (_distname, _version)
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try:
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etclsbrel = open("/etc/lsb-release", "rU")
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for line in etclsbrel:
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m = _distributor_id_file_re.search(line)
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if m:
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_distname = m.group(1).strip()
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if _distname and _version:
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return (_distname, _version)
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m = _release_file_re.search(line)
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if m:
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_version = m.group(1).strip()
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if _distname and _version:
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return (_distname, _version)
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except EnvironmentError:
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pass
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(_distname, _version) = platform.dist()[:2]
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if _distname and _version:
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return (_distname, _version)
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try:
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p = subprocess.Popen(["lsb_release", "--all"], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
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rc = p.wait()
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if rc == 0:
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for line in p.stdout.readlines():
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m = _distributor_id_cmdline_re.search(line)
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if m:
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_distname = m.group(1).strip()
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if _distname and _version:
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return (_distname, _version)
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m = _release_cmdline_re.search(p.stdout.read())
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if m:
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_version = m.group(1).strip()
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if _distname and _version:
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return (_distname, _version)
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except EnvironmentError:
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pass
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if os.path.exists("/etc/arch-release"):
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return ("Arch_Linux", "")
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return (_distname,_version)
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def get_platform():
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# Our version of platform.platform(), telling us both less and more than the
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# Python Standard Library's version does.
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# We omit details such as the Linux kernel version number, but we add a
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# more detailed and correct rendition of the Linux distribution and
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# distribution-version.
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if "linux" in platform.system().lower():
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return platform.system()+"-"+"_".join(get_linux_distro())+"-"+platform.machine()+"-"+"_".join([x for x in platform.architecture() if x])
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else:
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return platform.platform()
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