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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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#
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# GuessIt - A library for guessing information from filenames
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# Copyright (c) 2011 Nicolas Wack <wackou@gmail.com>
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#
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# GuessIt is free software; you can redistribute it and/or modify it under
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# the terms of the Lesser GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# GuessIt is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# Lesser GNU General Public License for more details.
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#
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# You should have received a copy of the Lesser GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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#
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import os.path
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def split_path(path):
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r"""Splits the given path into the list of folders and the filename (or the
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last folder if you gave it a folder path.
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If the given path was an absolute path, the first element will always be:
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- the '/' root folder on Unix systems
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- the drive letter on Windows systems (eg: r'C:\')
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>>> split_path('/usr/bin/smewt')
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['/', 'usr', 'bin', 'smewt']
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>>> split_path('relative_path/to/my_folder/')
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['relative_path', 'to', 'my_folder']
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>>> split_path(r'C:\Program Files\Smewt\smewt.exe')
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['C:\\', 'Program Files', 'Smewt', 'smewt.exe']
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>>> split_path(r'Documents and Settings\User\config\\')
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['Documents and Settings', 'User', 'config']
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"""
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result = []
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while True:
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head, tail = os.path.split(path)
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# on Unix systems, the root folder is '/'
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if head == '/' and tail == '':
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return [ '/' ] + result
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# on Windows, the root folder is a drive letter (eg: 'C:\')
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if len(head) == 3 and head[1:] == ':\\' and tail == '':
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return [ head ] + result
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if head == '' and tail == '':
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return result
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# we just split a directory ending with '/', so tail is empty
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if not tail:
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path = head
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continue
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result = [ tail ] + result
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path = head
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def split_path_components(filename):
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"""Returns the filename split into [ dir*, basename, ext ]."""
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result = split_path(filename)
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basename = result.pop(-1)
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return result + list(os.path.splitext(basename))
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def file_in_same_dir(ref_file, desired_file):
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"""Return the path for a file in the same dir as a given reference file.
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>>> file_in_same_dir('~/smewt/smewt.db', 'smewt.settings')
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'~/smewt/smewt.settings'
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"""
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return os.path.join(*(split_path(ref_file)[:-1] + [ desired_file ]))
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