#!/usr/bin/env python # -*- coding: utf-8 -*- # # GuessIt - A library for guessing information from filenames # Copyright (c) 2011 Nicolas Wack # # GuessIt is free software; you can redistribute it and/or modify it under # the terms of the Lesser GNU General Public License as published by # the Free Software Foundation; either version 3 of the License, or # (at your option) any later version. # # GuessIt is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # Lesser GNU General Public License for more details. # # You should have received a copy of the Lesser GNU General Public License # along with this program. If not, see . # import ntpath import os.path def split_path(path): r"""Splits the given path into the list of folders and the filename (or the last folder if you gave it a folder path. If the given path was an absolute path, the first element will always be: - the '/' root folder on Unix systems - the drive letter on Windows systems (eg: r'C:\') >>> split_path('/usr/bin/smewt') ['/', 'usr', 'bin', 'smewt'] >>> split_path('relative_path/to/my_folder/') ['relative_path', 'to', 'my_folder'] >>> split_path(r'C:\Program Files\Smewt\smewt.exe') ['C:\\', 'Program Files', 'Smewt', 'smewt.exe'] >>> split_path(r'Documents and Settings\User\config\\') ['Documents and Settings', 'User', 'config'] """ result = [] while True: head, tail = ntpath.split(path) # on Unix systems, the root folder is '/' if head == '/' and tail == '': return [ '/' ] + result # on Windows, the root folder is a drive letter (eg: 'C:\') if len(head) == 3 and head[1:] == ':\\' and tail == '': return [ head ] + result if head == '' and tail == '': return result # we just split a directory ending with '/', so tail is empty if not tail: path = head continue result = [ tail ] + result path = head def split_path_components(filename): """Returns the filename split into [ dir*, basename, ext ].""" result = split_path(filename) basename = result.pop(-1) return result + list(os.path.splitext(basename)) def file_in_same_dir(ref_file, desired_file): """Return the path for a file in the same dir as a given reference file. >>> file_in_same_dir('~/smewt/smewt.db', 'smewt.settings') '~/smewt/smewt.settings' """ return os.path.join(*(split_path(ref_file)[:-1] + [ desired_file ]))